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Subject:
GO Gages for Measuring Maximum Material Condition
Jim,
Measuring a hole (ID) at .126 plus .005 and minus .000. I use a .126
(plus) plug gage and the gage pin does not enter the hole. I assume
the hole is undersize and out of specification. The actual plus pin is
.1262. My supervisor says the hole is within specification because I
am suppose to use .126 (minus) plug gage.
The actual size is .1258. Is this true?
I think the gage pins should not be smaller than .126. I think the
minus pins are for the NO-GO and the plus pins are for the GO.
Maybe I am wrong, so please enlighten me.
I finally found your web site. I've been a loyal James D. Meadows fan since
the workshop you held in
Half Moon Bay
,
California
. I attended your
ANSI-Y14.5M-1994 training in August 1995. I do not have any more
people to ask technical questions of. I will return to your website
often and have registered to receive your newsletter.
Sincerely ,
Ken
Ken,
Jim
called in from the road and dictated his response to your question.
"Although
the ASMEY14.43-2003 Standard - Dimensioning and Tolerancing Principles for
Gages and Fixtures does not dictate gaging policies individual companies
must use, the preferred gaging policy, as defined in the ASME Y14.43
standard, is called the 'Absolute Gage Tolerancing Policy'.
The
Absolute Gage Tolerancing Policy says all gage pins are plus tolerance for
GO gages and functional gages and all gage holes are minus tolerance.
So, you are correct in saying your gage pin is a diameter of .126 all plus
tolerance and no minus tolerance. The recommended tolerance on gages is
5-10% of part tolerance. In this case, it would be 5-10% of the size
tolerance on the hole being gaged.
The
reason we do not prefer gage pins to have a minus tolerance is that we
(ANSI/ASME) do not want the gages to accept bad parts. The down side
of our policy is that it is possible for a borderline, technically-good part
to be rejected."
Nice
to hear from you. I hope our paths cross some time in the future
again.
James
D. Meadows, Chairman
ASME
Y14.43-2003 Standard - Dimensioning and Tolerancing Principles for Gages and
Fixtures
__________________________________________________________________________
Subject: Roundness
Jim,
How
are you doing? I hope all is well with you. Jeannie
called on Friday and I am waiting for the powers that be make a decision on
bringing you here. I hope they
make the right decision.
I have a question on roundness: Does an air gage truly check roundness
or just size?
Thanks,
Greg
Greg,
It
depends on the configuration of the air gage. Generally, they are
configured to probe just two opposite points on the diameter or three points
at 120 degrees from one another at a time. These configurations mainly
check the size. Technically, size is supposed to be inspected for
violations of a maximum material condition envelope with a simulation of a
GO gage. For a shaft, this would be a cylindrical gage hole that is as
deep as the shaft being inspected is long, and with a diameter of the MMC of
the shaft being gaged. Then, a two-point opposing point measurement
checks the least material condition (LMC). Most air gages are only
properly configured to accurately measure LMC.
As
far as roundness is concerned, if enough opposing points on the surface of
the cylinder being measured are taken and found to measure the same in size,
it is a rough check of roundness. It can be fooled into believing that
some parts that are not round meet the roundness requirement, but is a
reliable rough check for most produced configurations. Rough checks of
roundness are also taken by micrometer measurements (many) on shafts or
by putting a shaft into a V-Block and rotating it under a dial indicator
probe. Since none of these techniques stabilizes a central axis from
which measurements are taken, all can be fooled into believing parts that
are not round meet roundness requirements.
For
a more reliable roundness measurement, the axis of each circular
cross-section being tested must be stabilized, then each circle of the
surface swept with a probe. Each circle is re-zeroed, since this is
not a cylindricity measurement. This can be done with a chucking
device and a dial indicator, or if this is a critical, tight tolerance, a
roundness checking machine should be employed. There are many of these
machines available on the market, and they are very accurate and built just
for the purpose of checking roundness.
Hope
this helps,
Jim
__________________________________________________________________________
Subject:
PpK Tolerance
Mr.
Meadows
I received your name from a DCX supplier development engineer. We have
a question, and I hope you have a short quick answer.
Question: In determining a
capability (Ppk) of a hole position, which has a MMC in the
GDT block attached to that feature?
Example:
Position tolerance of a diameter 1 mm MMC to |-A-|-B-MMC|-C-MMC|
and the hole diameter has a tolerance of +/-1.0 mm.
In the process, I produce the part to +1.0/-0.0.
Can I then add 1.0 mm to the position tolerance when I calculate my
Ppk?
Hope this is clear and to hear from you soon.
Regards
Tom
Tom,
Yes,
you can.
Jim
__________________________________________________________________________
Subject:
Coplanarity
Jim,
Can you let me know if you believe the following method is valid for
checking coplanarity and why or why not. Personally I don't believe it is
but cannot come up with a valid reason. The feature in question is a
series of 500 pins with a coplanarity requirement of .006.
There
are 2 similar methods being used:
1)
The pin heights above the board are being measured and if the delta of the
highest and lowest pin is .006 or less it is considered acceptable.
2)
The top of one pin is "zeroed" and if the T.I.R. from that zero is
.006 or less then it is considered acceptable.
Neither
of the methods establish any sort of reference plane with respect to
the pins, the reference plane used is the opposite side of the board. What
I've seen in the past is that a reference plane is established either using
a surface plate setup or a CMM and then the TIR of the "surface"
is measured.
Thanks,
Bob
Bob,
Both
methods are correct for acceptance. Since the orientation (you didn't
mention a datum reference) is unimportant, if the delta between the highest
and lowest points of all probed points is .006 or less, the coplanarity is
met (that's all the control is really asking for). Also, if the full
indicator movement/total indicator readout isn't greater than .006 for all
points, then the tolerance requirement has been met. If a datum had
been referenced in the coplanarity control, then the relationship to that
datum would also have to have been met. But without a datum reference,
both methods are capable of determining the parts are good.
The
only thing to be cautious of is if the delta or the TIR is greater than
.006, it is still possible that the parts are good. If the points probed are
graphed out and the data is manipulated for orientation (angle) and found to
be able to fit within a .006 tolerance zone, then the parts are in
compliance with the tolerance. By setting the part up on a surface
that is not a datum feature, an additional error of orientation to the plane
formed by that surface is introduced. Since that is not part of the
requirement, if the additional error is great enough, it could cause a
compliant part to fail.
Jim
Meadows
__________________________________________________________________________
Subject:
Question about "TOLERANCE STACK-UP ANALYSIS"
Hello,
Jim
I
have purchased your book "TOLERANCE STACK-UP ANALYSIS" and have a
question about one of the exercises.
Exercise
8-5, problem #1 "answer" page.
I
am confused with the .130 pattern shift D(m). I would expect the
pattern shift to be .050. I come to that conclusion by reviewing pages
8-2 and 8-3, looking at the addition as shown of sheet 8-3.
Can
you please review this and explain to me what is going on.
Thank
you.
Matt
P.S.
I attended your class 2 years ago. I have found your book to be very
helpful. I am now trying to perform the tolerance analysis (stack up)
to verify functions and fits. I have realized so far that this is not
an easy task to perform. Your book "TOLERANCE STACK-UP
ANALYSIS", I find to be very useful.
P.S.S.
Please call me if would like to discuss this over the phone if that
is easier.
Matt,
The
figure on page 8-1 has a secondary datum feature of size with two different
virtual conditions generated by two geometric (position)
tolerances. One relates to the datums A, E and D, while the other
relates from hole to hole and to datum A only. The trick is to know
which one applies to the pattern of 28 holes being positioned back to this
datum feature (datum feature B). The answer is that the pertinent
tolerance (and virtual condition) is the one that applies to the datum(s)
that precede datum feature B (that is referenced at MMC in the 28 hole
pattern's feature control frame). The only datum that precedes B in
the 28 hole pattern's position control is datum A. Therefore the
pertinent geometric tolerance that can be derived from B is found in B's
position control that uses only the A datum. That tolerance is zero at
MMC, but .010 (bonus tolerance) at LMC. So, the maximum pattern shift
is a diameter of .010. Figure
8-1 follows:
For
the Exercise Figure 8-5, datum feature D has only one virtual condition
generated by one geometric (position) tolerance. It is .080 at MMC,
but .130 (.080 plus .050 bonus tolerance) at LMC. So, the maximum
pattern shift that can be experienced by the four hole pattern is a diameter
of .130.
Hope
this helps,
Jim
Meadows
__________________________________________________________________________
Subject:
GD&T Problem for Door Hinges
Jim,
I
was forwarded your contact information from Jimr at DCX, as he suggested
that you might be able to help our group resolve a GD&T issue with door
hinges - specifically flatness on the mounting surfaces. Our issue is
plainly this, for the mounting surfaces of the hinge which attach to either
the pillar or door, we currently have a flatness callout attached to each
corresponding hinge surface. However, the assembly plants are finding that
when the flatness of the part moves to a convex nature - it can produce
"rocking" in the hinge when the bolts are driven one at a time.
This results in repeatability issues.
We
think that the best way to solve this is to ensure that the hinge mounting
surfaces are always "flat to concave" in order to eliminate this
"rocking" from a convex part.
Attached
is a proposed GD&T scheme to try and specify this type of control. Could
you take a moment and review the attached GD&T scheme and forward your
comments / recommendations?
Thanks
in advance for your assistance on this,
Brad
Brad,
First,
I don't understand why you are using a profile control on datum feature A.
It looks like one continuous planar surface. It seems like a simple
flatness control would serve it best. The problem with applying
profile of a surface to it and referencing datum targets A1, A2 and A3 is
that they will form datum plane A and the profile tolerance zone is equally
split on either side of datum plane A. This isn't always a problem,
but it could have the effect of denying you half of your tolerance zone if
the datum targets happen to contain the highest or lowest points on the
surface. If that was the case, the zone outside of datum plane A (half
of the 0.3 tolerance) would contain none of the surface, and the other half
of the zone (the other 0.15) would have to contain the entire surface in
order to be in compliance with the geometric tolerance. If datum
feature A is just one continuous planar surface, a flatness tolerance would
be less restrictive, allowing the entire surface to occupy the 0.3 tolerance
zone. This flatness control would reference no datum. After
that, if you feel you need datum A for some other subsequent surfaces
(or holes, shafts, etc.) to reference back to, you could still establish
datum targets A1 through A3 if you want to. But they would have
nothing to do with this control.
The
other issue is one that I have run into quite a few times. On the two
coplanar surfaces you definitely need a profile of a surface for coplanarity
control. Calling each of them flat, or calling one flat and profiling
the other back to the first makes very little sense (since they work
together acting as though they are one surface). The solution you
propose is interesting. Let's talk through it. Since you are
going to set up on the three datum target areas, the tolerance zone will
split at the datum plane and become equal bilateral (plus and minus 0.3).
This would mean that the middle of the part could still be the highest
points. Since the tolerance zone is a total wide profile zone of 0.6
(according to the illustration you sent me), that means the middle points
could still be 0.3 higher or lower than datum plane B. The last
illustration you show says that condition would allow the part to rock over
onto one of the two surfaces and give you a 0.43 degree angle and a high of
1.41 from one surface to the other. If this situation was
unacceptable to you, the proposal you show for a change doesn't seem to
correct the problem. It seems to leave you in the same boat.
Now
to correct the problem. Hmmmm.....pretty tricky situation. Here
are some possibilities. 1) Just tighten the coplanarity (profile of a
surface) control to something that you can live with and get rid of the
datum targets (since they don't seem to be helping). 2) Call out the
two surfaces coplanar (using profile of a surface) to within 0.3 (or
something) without the datum targets (so that you get to use the entire 0.3
tolerance zone without it splitting), then make one of the two (entire)
surfaces a datum feature and reference the other parallel to it to
within a tighter tolerance than 0.3. 3) Use the coplanarity control
(again, I can't see the need for the datum targets, but of course, that's up
to you), then below the control say "SEE NOTE 27" (or whatever
number the note is) and in this note (which I would actually show as an
illustration) convey the same concerns you show in the "rocks"
illustration you sent to me. But instead of that illustration, show
the limits of angle (something considerably smaller than 0.43 degrees, I
assume) that you are willing to put up with, when the part does rock.
I like this approach because it lays out your specific concern, sets the
limit for the rock you will accept as a maximum number of degrees and
clarifies the coplanarity control better than the limits of geometric
tolerancing symbology have evolved to yet.
That's
all I can think of right now. If this isn't helpful, feel free to
write again and I'll take another crack at it.
Jim
__________________________________________________________________________
Subject:
RSS
James,
Is there a percentage probability of the RSS use in tolerance stack-ups?
What does RSS really tell us? Is there a sigma value?
I
am getting beat up over this by my manager. Help me Please. Thank you.
Jackie
Jackie,
You
have to understand, I don't really enjoy conversations about statistics.
I am not a "statistics zealot". But the information in my
books is well researched and time tested. I convey information that
has been created by reliable sources and add to them only the missing pieces
of puzzles required to apply them to tolerancing (in this case, statistical
tolerancing).
Now
that I've bored you to death, I will quote from Quality Assurance Pamphlet
AMSTA-P-702-116 (August 1967), entitled Statistical Tolerancing-A Solution
to Procurement Problems-US Army Tank Automotive Command. This
extensive pamphlet is 59 pages long and has a bibliography too long to list
here. It says, in referring to the RSS method for calculating
something it calls "natural tolerance", the tolerance likely to be
consumed in an assembly produced to a Gaussian Frequency curve, "The
dimension is then designated as the median, plus and minus 3 standard
deviations The total natural tolerance is therefore 6 standard
deviations. The natural tolerance represents process capability and will
include 99.7 percent of the dimensional values obtained with the
process." "This approach to assembly tolerancing is the
"statistical" method. Derived from well established basic
probability theory, it may also be written as follows" it goes on to
state the Root Sum Square formula here (the tolerance of the assembly likely
to be consumed is equal to the square root of the sum of the tolerances on
the individual components squared). Then says, "Examination indicates
that this statistical assembly tolerance represents the tolerance that will
be achieved on 99.73 percent of the assemblies..." and from my
own book on Tolerance Stack Up Analysis, in Chapter 11, "a) Using
the derivation of the Pythagorean theorem called the RSS (root sum square)
formula, calculate the statistical probability for the assembly (the natural
tolerance likely to be used during manufacture) b) Determine the
percentage ratio between the statistical probability tolerance and the
previously calculated 100% assembly tolerance and c) Determine the increased
statistical probability tolerances to be redistributed to the assembly's
component parts."
There
is much more information on this topic in the pamphlet and in my book,
but I believe that is all you asked. If you need more information on
this topic, please feel free to write again. I will be out of the
office until the weekend, but will respond when I return.
Hope
this helps,
James
D. Meadows
__________________________________________________________________________
Subject:
RE: RSS
Thank
you. Thank you so much. I will get my hands on the spec. and give it to him.
Jackie
Subject:
Question on Page 45, Fig. 3-4, of Your Book on Geometric Dimensioning and
Tolerancing?
WORKPIECE
FUNCTIONAL
GAGE
Mr.
Meadows:
I
am attempting to contact you because I have no expert to consult here at the
office. (It is my mission to become the "office GD&T
expert"). I am studying your book, Geometric Dimensioning
and Tolerancing: Applications and Techniques for Use in Design,
Manufacturing, and Inspection, (11th printing) and companion workbook
on my own and I am confused by what I perceive to be an error on page 45,
figure 3-4. I think that the unilateral tolerances applied to the Ø.550
pins and the Ø2.994 I.D. should be swapped because, as printed, those
features at MMC interfere with the MMC virtual condition boundary of the
mating holes. (Should be 5X Ø.550 +.000/-.002 and Ø2.994
+.002/-.000) Am I correct or do I need to read it from the beginning
again?
Respectfully,
Michael
Michael,
It
is not an error. Page 45 shows
the gage, not the mating part. The gage policy of the American
National Standards Institute (ANSI) is to not accept a bad part. We
must therefore tolerance our gages to reject a few borderline technically
acceptable parts. The policy is that functional gage pins begin at the
virtual condition size of the holes they inspect and are then toleranced
with all plus tolerance (gage pins can only be toleranced to be larger than
the virtual condition of the holes they inspect). Conversely, gage
holes begin at the size of the virtual condition of the features they are to
inspect and are toleranced to be all minus, so as to accept no
out-of-tolerance parts. The type of gage tolerancing shown is called
"Practical Absolute" gaging (described as a gage that will in
practicality never accept an out-of-tolerance part. It is best
described in the ASME Y14.43-2003 standard on Dimensioning and Tolerancing
Principles for Gages and Fixtures.
Hope
this helps,
James
D. Meadows
Chairman
Y14.43
__________________________________________________________________________
Subject:
Question About an Example on Pages 198 & 199 in Your Book.
WORKPIECE
WITH 5 HOLES (Page 198)
CALCULATING
MINIMUM WALL THICKNESS
Dear Mr. Meadows,
I contacted you earlier few times and you were very prompt in your responses
and I sincerely thank you for that.
While I was going through your book, I have a doubt and following is the
description to the best of my ability.
The question is in reference to Example problem on Page 199 of your book
Geometric Dimensioning and Tolerancing.
Movement of D due its change from MMC (VC) to LMC = 1.000-.600 = 400
It also moves additionally because of reference to datum B at MMC. This
movement is equal to 5.000-4.990 + .030 as B (since it is a datum of size)
moves from MMC (VC) to LMC = .040
(They are VC as they being secondary datums, should be considered at VC)
Therefore total movement of D is .440 instead of .400 as shown in the book.
?????????????
In other words, applying the logic item 2 given below on the same page,
which states
“If D is related to B and the 4 holes are related to D, then the 4 holes
as a pattern are related to B to within the sum of their relationship to D
and D’s relationship to B”
4 hole relationship to D = 1.000-.600 = .400
D’s relationship to B = its own (1.000-.600) + Additional movement due to
B “s change from MMC to LMC = .040 = .440.
In the next example, applying the same logic,
“.130 Allowed movement of feature D at LMC to C” is correct as C is a
planar datum.
So I feel that since in the earlier example datum B is a feature of size and
not a planar datum the value will be .440 instead of .400
I would very much appreciate your response at your earliest convenience.
Also I have two general questions for you as you are on the ASME committee:
1. In Y14.5, why is it necessary
to specify “R” for slots (It used to be R FULL earlier I think). If it
is not R Full the R (radius) has to be specified. In other words, if
nothing is specified it is R Full. (Figures 1-27, 1-28 and 1-35)
2. Same question about THRU for
holes. If not THRU depth has to be specified. (Fig. 1-34)
Regards,
Sundar
Sundar,
It's
nice to hear from you again. The answer to your primary question is
that you have already used the .040 in the calculation of the Resultant
Condition of datum feature B (4.990-.040=4.950). In this case, you
don't get to use the .040 twice. To understand why, we must understand
how B is represented in a gage that would inspect the center hole.
Since the gage would represent datum feature B at its virtual condition of
5.030, any pattern shift allowed for the center hole would be reliant on the
slop/airspace created by the departure of datum feature B from its virtual
condition size (of 5.030) in that gage. Since we already used up that
.040 in perpendicularity tolerance when we calculated the resultant
condition of datum feature B (4.990 + .040=5.030), the gage would be
the same size as datum feature B. There would be no slop/airspace
between the gage and datum feature B. There would therefore be no
additional pattern shift for the center hole. Had we not used the .040
in the calculation on the Resultant Condition of the OD (datum feature B's
calculation on the top of page 199), then we could have used it for
pattern shift on the center bore. But we don't get it twice.
As
far as the center hole getting .400 diameter position tolerance at LMC, it
does (of course) get that much. And as far as the four-hole pattern
(.370-.375 holes) getting it again because they are referenced to datum
feature D at MMC, it would. The reason is that the four holes are
measured from different datums than the center hole (for positional
movement). Every time you are positioned from different datums, you
switch gages (or set-ups). And every new gage (or set-up accumulates
tolerance (error). So, each new set of location datums means a new
gage. And every new gage begins anew and can receive the tolerance
from any feature represented by the gage.
So,
the simple answer here is that perpendicularity does not react like position
does. Being out of perpendicularity on datum feature B, in this case,
eliminates slop in the assembly and the pattern shift that the four holes
would have been entitled to. But had we assumed perfect
perpendicularity on datum feature B, the .040 would not have been used to
calculate the Resultant Condition of the OD (datum feature B) and would
instead have been used as you describe it in your email, as pattern shift
for the center hole, raising the tolerance for the center hole of .400
diameter for movement (due to the MMC symbol after the .000 positional
tolerance) by an additional .040 for shift (due to the MMC symbol after
datum feature reference B). But with either usage, the final answer to
the problem would have been the same, having used the total amount of
tolerance.
As
to your general questions, I don't see questions there. I see
statements right out of Y14.5. And that is the answer. Because
the Y14.5 standard says those are the rules, they are. I know people
always hate that answer, but not everything is true because of logic in the
standards. Sometimes it is just true because that is what everyone
could agree on the day it was written.
I
am leaving on a road trip tomorrow and am not taking my computer. If
you have more questions, please feel free to write, but realize I won't be
able to respond until I return next week.
As
always, I hope these answers helped.
Jim
Meadows
__________________________________________________________________________
Subject:
Straightness and Circularity
Greetings,
Jim...
I've looked in both the ASME standard and your book to try to confirm or
refute an idea of mine. I couldn't find anything to challenge my thinking,
so I thought I'd ask you.
Can
straightness and/or circularity apply to a hole?
If so, how does one measure it? If
so, what does one use for virtual condition?
Form
tolerances for a pin in a (virtual condition) hole for inspection, I
understand. I think that size and location are enough to control a hole.
Comments?
Best
regards..
Ted
Ted,
Straightness
and circularity can most certainly apply to a hole. Circularity can be
inspected by a CMM (best using a constant contact scanning probe) or even a
dial indicator attached to a rotating spindle. Straightness is a more
versatile control and can be used on a hole as a surface, axis (derived
median line) or center plane (derived median plane) control. If used
as an axis or center plane control at MMC, it can be inspected with a gage
made at the virtual condition (MMC minus the geo. tol. at MMC) size.
If used as a surface control, straightness, like circularity (which is
always used as a surface control) generates no virtual condition and must be
contained within the size limits (may not exceed an envelope of perfect form
at MMC-according to Rule #1). These controls (circularity and
straightness) can be inspected with a dial indicator or CMM. Of
course, a roundness checking machine is made for the circularity
measurement.
Size
tolerance, under Rule #1 controls roundness, straightness and taper, unless
you override it with a refinement surface control, or refine or loosen it
with a control of straightness on the axis or center plane.
Then, position tolerance controls angles and location. So, I
would agree that size tolerance and position tolerance is usually sufficient
to control most holes. There are only four things that geometry can
control, they are size, form, angles and location. A hole's size
tolerance controls its size and form, and a position tolerance controls
angles and location. That's all there is.
Hope
this helps,
Jim
__________________________________________________________________________
SUBJECT:
Really Badly Applied Dimensioning and Tolerancing
Jim,
I
was recently fortunate enough to find another job with the defense industry.
Having been laid off from the automobile industry, along with
thousands of my co-workers, I was worried I would end up flipping burgers
and wearing a paper hat. But war
is in now, so the country needs more equipment (tanks, guns, ship, jets,
etc.) and disposables (bullets, bombs, grenades, etc.) with which to conduct
it.
I'm
grateful not to be poor and homeless, but I'm shocked at just how poorly the
products I'm seeing are dimensioned and toleranced.
Don't get me wrong. Things
were far from perfect in the automobile industry, but the situation in the
defense industry is ridiculous. How
do these products ever work? From
some of the nightly news shows and some of the reports I've personally seen,
I think the answer is that they often don't.
And when they do, it is because each piece is hand fitted (ground,
filed, bent and forced to fit), even though we are sometimes making them in
large quantities. How
inefficient is that? We could
never have gotten away with that in the auto industry.
The cost of every mid-sized sedan would be $150,000 or so.
But they get away with it here! Our
tax dollars at work. These
people need training, and a lot of it.
Is
there a solution to this problem that's likely to be implemented in the near
future?
Ken
Ken,
No,
there isn't. Training is, of
course, the easy answer. But,
tolerancing is something that is so complex, it takes a long time to learn
to do it well. And most
companies, including those doing defense work, look for a quick fix.
I recently had a request for a 1-day "refresher" course
from a Director of Engineering for his group.
I told him 1-day courses simply don't provide enough information, but
I would be happy to do a longer course.
He wrote back and said his people only needed a refresher, because
they already knew the topic. And
he said he had personally attended 1-day courses in the past that were very
successful. There are so many
thing wrong with that statement, I hardly know where to begin.
But I'll try.
1.
Applying dimensions and tolerances to an assembly is a job as complex
as any other profession. You
can't learn to do any job well in 1-day, unless it's on the level of
learning to replace the cap on a toothpaste tube.
2.
If you think your group needs a "refresher" course, you
must have noticed they aren't very good at using GD&T.
Noticing these problems should have alerted you to the fact that they
aren't knowledgeable and don't just need a "refresher" course.
3)
If people are going to be any good at this, they need a series of full-blown
courses. Not even a full week of
training is going to teach them to do this job well.
It takes at least several courses administered at calculated
intervals. The course should be
of varying levels of difficulty (basic, intermediate, advanced) and with
different job emphasis (design, inspection, manufacturing, gage and fixture
design/use, tolerance stack-up analysis, etc.).
4)
This topic should be treated as though you were educating the people as
thoroughly as in any major in college.
Of
course, most companies and those supervisors, managers and directors in
charge, will never believe that and even if they did, they wouldn't commit
the time and money necessary to accomplish it.
That doesn't make them bad people.
It just means they don't comprehend the magnitude of the problem and
the difficulty of training their people well enough to solve it at.
Jim
__________________________________________________________________________
Subject:
Gauge Tolerance and Part Acceptance
Jim,
After reading the appropriate sections of your book, "MEASUREMENT OF
GEOMETRIC TOLERANCES IN MANUFACTURING", I believe I have an
understanding of appropriate tolerancing for functional gauges. The question
I have is can I backtrack from the gauge tolerance and say this gauge will
accept a feature with a true position of a specific amount?
I have a .012 plus and minus .001 diameter pin connector located on .050
basic grid, with a true position tolerance of a diameter of .003 @ MMC to A
and B (A being the lower row of pins, B being the left hand row of pins).
Now if the gauge being used has holes the measure .018 diameter and are held
to a true position of .001 (I'm not if this is at MMC so lets assume the
gauge is RFS).
The Connector pin virtual condition is .016, in my opinion the gauge holes
should be .016 +0000/-.0001, and the position tolerance should be .0003 at
MMC ( or any combination of these tolerance). Since the hole diameters in
the gauge measure between .017 and .018 and the holes in the gauge are being
held to a position tolerance of .001 can I say that gauge will accept parts
with a true position of .0056 (the original .003 plus the
additional .002 from the gauge hole sizes plus the .0006 additional position
tolerance from the gauge).
Regards,
Bob
Bob,
I'm sorry Bob, but I just can't figure out what you are trying to do here.
The only sentence that I understood and really agree with is the one that
says, "The Connector pin virtual condition is .016, in my opinion the
gauge holes should be .016 +.0000/-.0001, and the T.P. tolerance should be
.0003 at MMC." If the pin has .013 MMC and a position tolerance
of .003, then that statement is correct. But the rest of it is
difficult for me to understand. If the virtual condition of the pins
is .016, then the gage holes should be .016, not "between .017 and
.018" (to check the position tolerance on the connector pins).
So, that's confusing.
The
gage holes are too big, so they will accept bad parts. Gage tolerances
don't add to the tolerances of the parts being inspected. They
subtract from it. And even though the shafts being inspected are
controlled at MMC, if these shafts are entitled to a "bonus"
of position tolerance, they get it because they are produced smaller than
their MMC, not because the gage holes have been produced too large.
So, the thing you are trying to do doesn't seem to be possible-taking the
fact that the gage buys bad parts because its holes are too big and that the
gage has tolerances and saying that proves the gages can accept pins
that are out of position a certain amount. This can't be determined.
First,
we don't know how much position tolerance the pins are entitled to until we
know the pin diameter. Second, the position tolerance on the gage
holes subtract from the pins' tolerance, they don't add to it. Third,
yes their is some connection between 1) the gage holes are too big and 2)
this affects the amount of position tolerance the pins may use and still be
accepted by these (wrong) gages, but we can't know how much position
tolerance the pins have used up, until we know what the pin diameters are as
produced. If you measured the pin diameters as produced and then
subtracted that from the gage hole size, that would tell you how much
out-of-position tolerance for the pins the gage hole will accept (if
you subtract the position tolerance on the gage hole).
But,
I have to say, the only solution that makes any sense to me here is to get
new gages.
Jim
Jim,
I
also believe that the supplier needs new gages.
In the meantime, I’m trying to quantify how much error will be
accepted by the gage currently being used by the supplier.
From you previous response, I believe I can use the following
formula:
Out-of-Position
allowed by the gage=gage hole size minus actual pin diameter minus position
tolerance on gage hole
So,
in my case, we have:
Actual
pin diameter: .012 (this is fairly consistent due to the manufacturing
method)
Gage
hole position tolerance: .001
Gage
hole size: .017 to .018
Out-of-position
tolerance allowed by the gage=.017 minus .012 minus .001=.004
Since
the actual gage holes vary from .017 to .018, I can say that the gage will
accept parts out-of-positional tolerance between .004 and .005.
Bob
Bob,
That
sounds right, unless the gage hole doesn’t use its .001 of position
tolerance. If the gage hole was
perfectly positioned, you would have to add that .001 to the .004 to .005 of
out-of-position tolerance (of the pins being gaged) that the gage holes
would accept.
Jim
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